saul wrote:Goldminer wrote:
What could be more convenient that just realizing that light has the latency of one foot per nanosecond (in any direction)?
Indeed. This is the fundamental postulate of special relativity you have restated.
Primarily, one foot per nanosecond in the "at rest with the source frame." This is the reference frame where all Earthly bound sources are measured.
saul wrote:Goldminer wrote:
I have pointed out many times that it is the location of an observer, regardless of motion and "reference frame," in relation to the distances from various "events" that determine the order of events witnessed by said observer. The order of "events" radiated by any source, anywhere, are fixed by the order in which they are radiated. They will never change no matter who, when, or where they are observed.
Unfortunately your statement here is in contradiction to your earlier statement that light always has the same speed in any reference frame.
Sorry my friend, you didn't follow my logic. The light emanating from some object carries the information that makes the picture that we see. For an example we are watching (from a nearby location) the face of a clock which includes a calendar. The series of events emanating from the clock will always show the passage of time in the order that it did, regardless of who observes it over time, where they are located, or how fast they are going.
However, another identical clock regulated identically and set to the exact same epoch, emitting the same series of passage of time events; but located far from the observer in this same reference frame (i.e. when the two clocks are reunited a the same location they indicate the exact same time and date) will be seen to be giving the time as lagging the local clock, by the latency of the light signal over said distance. The order of the passage of time does not get out of order for either clock. The synchronicity of the indicated time does vary, and moving the distant clock closer will have the effect of making it's passage of time appear to pass faster that the local clock, merely because of the decrease in latency of the signal.
saul wrote:Please forgive me while I entertain a simple gedanken experiment to explain.
An observer (Alice) is midway between two light sources (A and B) in a line (lets call it the X axis). She is at rest with respect to both light sources. She can verify her position and that each source is the same distance away by e.g. sending out some light in each direction and then watching these pulses return from each side at the same time.
Now the light sources are each activated at some time.[Goldminer- activated simultaneously, and still in Alice's reference frame, I presume] Each emits some pulse of light. We would like to say which emission event took place first, or order them temporally. Alice observes the light from each source arriving at her location simultaneously. What does she conclude? She concludes that the emission events at A and B were simultaneous. With me so far?
Now along comes Bob, who happens to be in a hurtling in from stage left along the X axis. His arrival is timed so that as he passes the exact position of Alice she is just receiving the two signals from the emission events that we are concerned with.
Allow me to interrupt here a moment, Saul; If we assume that A is on the left and B is on the right, with dear Alice in between, Bob just went by A in order to get to Alice, right? Let's, just for my point, assume that Bob arrived a A just as it emitted the light pulse. He would see the pulse just as it was emitted, without any latency, right? (He will experience Doppler shift, right? Blue shift to be exact.) Now, if there was another Bob, Bob Jr. in front of Bob, spaced far enough out in front of Bob to arrive at Alice, just as the light pulse from A overtakes him and Alice, Bob JR. would see the light pulse A arrive with red shift, just as Alice sees it without the Doppler shift, right, Saul?
The oncoming light pulse from B reaches Bob Jr. and Alice at the same time as the pulse from A, but Bob Jr. sees this pulse blue shifted, right, Saul? Bob will also see the B pulse blue shifted, but he sees it before he gets to Alice's position.
saul wrote:Of course, as he is co-located with Alice his detectors also observe the flashes of light to arrive at his location simultaneously. Now what does Bob conclude?
Bob also is able to verify that at the moment of this detection the two sources are equidistant from him. However, this means that the two light sources were NOT equidistant from him at any earlier time (nor will they be equidistant at any time in the future, as he is moving with respect to them at speed V. Of course Bob also knows as you do that light takes some time to travel and so he knows that any moment of emission took place prior to when arrived at Alice's position, prior to when the sources were equidistant from him, i.e. when the sources were not equidistant from him.
Lets review: Bob accepts your postulate to call the speed of light a constant, and thus knows that the light was traveling the same speed from each source. He also knows the light from each source arrived at his midpoint location simultaneously. The only conclusion that Bob can draw is that the times of emission of light were not simultaneous! As Bob approaches Alice's center position the clock behind him is closer to him than the clock in front of him. Then when he arrives at the center the pulses arrive at his position simultaneously. In Bob's reference frame, the event which is the emission of light from the forward clock must have been AFTER the event which is the emission of light from the clock to his rear.
What ever the two Bobs think is irrelevant. The position of the emission of B's pulse can be determined in Bob's reference frame by stipulating another Bob (the third) who is out in front of Bob Jr, just enough to be at B when the pulse there is emitted. The three Bobs can determine their distances apart in their own reference frame without the aid of clocks. The facts are that the speed of light in Alice's frame is known to be c. We can follow the path of each pulse, and the two or three Bobs in Alice's reference frame. Bob sees A's pulse blue shifted, and B's pulse blue shifted. Bob Jr. sees A's pulse red shifted, and B's pulse blue shifted. Bob the Third also sees A's pulse red shifted, and B's pulse blue shifted. Once the two pulses are detected by the parties, none of them will ever see those pulses again.
But you have missed
the order of events problem in the "at rest with the sources" reference frame, where sources and observers are all at rest with each other. As I am trying to desperately point out, the order of events from sources distant from each other in the
at rest frame will be ordered differently by observers placed in different locations
at rest with this reference frame.
I sense a disturbance in the farce.