Strong Force geometry
If fusion of two protons follows the posturing shown in the simulation called “Special Collision between 2 protons” we can deduce the fusion geometry and associated pattern of distances between the six quarks. This allows us to calculate the nine forces between them in accordance with Coulombs Law.
Five of these vectors produce repulsion while four produce attraction. The sum of the nine forces is here suggested to be Strong Force.
By increasing the distance between the two protons we can also calculate when strong force goes to zero, or ceases to exist. Beyond this distance the nine force vectors combine into a repelling force, as expected between two bodies of similar charge. The calculations show that when the distance between the protons is increased on the order of one proton radius the strong force becomes zero and changes sign and name. At further distances it becomes the repelling force that we have come to expect between bodies of similar charge.
In other words:
Proton Radius, Strong Force and Binding Energy
Existing observations and measurements suggest that: “Strong force between two protons binds the protons with about 25 MeV of energy. The electromagnetic forces repel it with slightly less. The result is that about 1 MeV of energy would be required to split the two protons apart”. 1MeV = 1.602*10^-13 Joule.
The above proton simulations suggest a specific quark posture between the two protons:
Please see figure at:
http://www.dipole.se
Applying Coulombs law to the nine force vectors between the six quarks yields a calculation of the Strong Force shown below:
Please see table at:
http://www.dipole.se
The above lets us calculate the ES Strong Force as a function of the effective proton radius.
We can also iterate the calculation to find the separation distance between the protons where the ES Strong Force goes to zero.
We can also determine how the force varies with the separation distance and integrate the energy under the curve to determine the binding energy between the two protons.
The proton radius is generally assumed to be in the range of 10^-14 to 10^-15 meter.
However, if the proton radius is set to 3.55*10^-15 meter we get the following results:
ES Strong Force between two protons is 160 Newton.
The ES Strong Force has a reach of 0.785 times the radius of the proton or 2.785*10^-15 meter.
The ES Strong Force at half its reach is 35 Newton.
ES Binding Energy between two protons is 1MeV or 1.602*10^-13 Joule, and corresponds to earlier reported data.
Please note that the proton radius has been selected to give the above results but falls well within the earlier known range.
Summary:
The binding energy between two protons is known to be about 1.602*10^-13 Joule.
If the proton radius is 3.55*10^-15 meter, Charge Posturing and ES forces between the two protons produce a Strong Force of 160 Newton.
At a separation distance of 0.392 proton radii or 1.392*10^-15 meter the ES Strong Force has dropped to 35 Newton.
At a separation distance of 0.785 proton radii or 2.785*10^-15 meter the ES Strong Force has dropped to zero and continues as a repulsion force at larger distances.
If anybody has more accurate data about the binding energy between two protons or the radius of a proton I would very much like to hear from you.
