Miles Mathis 'What is G?'
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Miles Mathis 'What is G?'
What is G?
by Miles Mathis
...
I will refer you to my UFT paper for the full derivation of the separated equations. Suffice it to say, here, that gravity is expressed only by acceleration. Gravity is the acceleration of a length or a differential. This means that the gravitational “pull” of a body is determined only by its radius. Density, and therefore “mass”, is only a concern of the foundational E/M field. Which is to say that density considerations enter Newton’s equation only through the E/M field. Two spheres that are the same size have the same gravitational field, by definition. If they have different total fields according to Newton’s equation, it is because their densities are different; and their total fields are different only because one has more constituent quantum particles, and therefore more photon radiation.
This means that if the Earth were denser, you would weigh less, not more. You weigh less on the Moon not because it is less dense, or because it has less mass, but because its foundational E/M field is stronger. And its foundational E/M field is stronger because the Moon’s radius is smaller than the Earth’s. Although the Moon’s body is less dense, as a whole, its E/M field is more dense, on the surface. And this is simply because it has so much less surface area than the Earth (13 times less). You can’t just look at mass or density, you have to look at field lines; and the density of those field lines at the surface determines the strength of the foundational E/M field.
http://milesmathis.com/g.html
by Miles Mathis
...
I will refer you to my UFT paper for the full derivation of the separated equations. Suffice it to say, here, that gravity is expressed only by acceleration. Gravity is the acceleration of a length or a differential. This means that the gravitational “pull” of a body is determined only by its radius. Density, and therefore “mass”, is only a concern of the foundational E/M field. Which is to say that density considerations enter Newton’s equation only through the E/M field. Two spheres that are the same size have the same gravitational field, by definition. If they have different total fields according to Newton’s equation, it is because their densities are different; and their total fields are different only because one has more constituent quantum particles, and therefore more photon radiation.
This means that if the Earth were denser, you would weigh less, not more. You weigh less on the Moon not because it is less dense, or because it has less mass, but because its foundational E/M field is stronger. And its foundational E/M field is stronger because the Moon’s radius is smaller than the Earth’s. Although the Moon’s body is less dense, as a whole, its E/M field is more dense, on the surface. And this is simply because it has so much less surface area than the Earth (13 times less). You can’t just look at mass or density, you have to look at field lines; and the density of those field lines at the surface determines the strength of the foundational E/M field.
http://milesmathis.com/g.html
We live in a double star system.
We need to study double star systems.
Solar System as 4D energy vortex
http://files.kostovi.com/8835e.pdf
We need to study double star systems.
Solar System as 4D energy vortex
http://files.kostovi.com/8835e.pdf
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- Joined: Tue Jul 20, 2010 2:20 pm
Re: Miles Mathis 'What is G?'
What??!! Which is it, magnetic field or e/m strength?This means that if the Earth were denser, you would weigh less, not more. You weigh less on the Moon not because it is less dense, or because it has less mass, but because its foundational E/M field is stronger. And its foundational E/M field is stronger because the Moon’s radius is smaller than the Earth’s. Although the Moon’s body is less dense, as a whole, its E/M field is more dense, on the surface. And this is simply because it has so much less surface area than the Earth (13 times less). You can’t just look at mass or density, you have to look at field lines; and the density of those field lines at the surface determines the strength of the foundational E/M field.
.
How does photon e/m create gravity?
"It is dangerous to be right in matters where established men are wrong."
"Doubt is not an agreeable condition, but certainty is an absurd one."
"Those who can make you believe absurdities, can make you commit atrocities." Voltaire
"Doubt is not an agreeable condition, but certainty is an absurd one."
"Those who can make you believe absurdities, can make you commit atrocities." Voltaire
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Re: Miles Mathis 'What is G?'
@ Sparky
The Electron Orbit
(the greatest hole in Quantum Mechanics)
by Miles Mathis
"It used to be that a person who could come up with a simpler, more transparent explanation was a better physicist. That is no longer the case. Now the person that can come up with the more convoluted, mysterious, wordy, and illogical explanation is the better physicist, since such an answer must seem more “profound.”
Of course, I would not bring up this problem and treat the opposition with such contempt if I did not have a better answer for it. Fortunately, I do, one that happens to be very simple and direct, as well as mechanical. I have shown in a series of papers that if we make the charge force mechanical, we must get rid of the messenger or virtual photon that is now said to mediate it. We must replace that virtual photon with a real photon, and give it mass equivalence. Moreover, we must make all force repulsive. There is simply no way to explain attraction mechanically, so we give up on attraction, at the foundational level. Underlying both electricity and magnetism, we have the charge field, or what I now call the foundational E/M field. Although electricity may be either positive or negative, the foundational E/M field is always positive. It is always repulsive. This means that all protons and electrons are emitting real photons, and that all protons and electrons are repulsing all other protons and electrons, via simple bombardment. Attraction is explained by noticing that protons repulse electrons much less than they repulse other protons. In this way, the attraction is a relative attraction. Relative to the speed of repulsion of protons with one another, electron appear to move backwards. If protons are defined as the baseline, then electrons are negative to this baseline.
Classically, this can be explained by the size difference alone. Due only to surface area considerations, electrons are able to dodge much of the emission of protons and nuclei, and so they seem to swim upstream."
http://milesmathis.com/elorb.html
The Electron Orbit
(the greatest hole in Quantum Mechanics)
by Miles Mathis
"It used to be that a person who could come up with a simpler, more transparent explanation was a better physicist. That is no longer the case. Now the person that can come up with the more convoluted, mysterious, wordy, and illogical explanation is the better physicist, since such an answer must seem more “profound.”
Of course, I would not bring up this problem and treat the opposition with such contempt if I did not have a better answer for it. Fortunately, I do, one that happens to be very simple and direct, as well as mechanical. I have shown in a series of papers that if we make the charge force mechanical, we must get rid of the messenger or virtual photon that is now said to mediate it. We must replace that virtual photon with a real photon, and give it mass equivalence. Moreover, we must make all force repulsive. There is simply no way to explain attraction mechanically, so we give up on attraction, at the foundational level. Underlying both electricity and magnetism, we have the charge field, or what I now call the foundational E/M field. Although electricity may be either positive or negative, the foundational E/M field is always positive. It is always repulsive. This means that all protons and electrons are emitting real photons, and that all protons and electrons are repulsing all other protons and electrons, via simple bombardment. Attraction is explained by noticing that protons repulse electrons much less than they repulse other protons. In this way, the attraction is a relative attraction. Relative to the speed of repulsion of protons with one another, electron appear to move backwards. If protons are defined as the baseline, then electrons are negative to this baseline.
Classically, this can be explained by the size difference alone. Due only to surface area considerations, electrons are able to dodge much of the emission of protons and nuclei, and so they seem to swim upstream."
http://milesmathis.com/elorb.html
We live in a double star system.
We need to study double star systems.
Solar System as 4D energy vortex
http://files.kostovi.com/8835e.pdf
We need to study double star systems.
Solar System as 4D energy vortex
http://files.kostovi.com/8835e.pdf
- D_Archer
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- Location: The Netherlands
Re: Miles Mathis 'What is G?'
With field he does not mean magnetic field, just the field of the photons that are at the basis of the E/M field.Sparky wrote:What??!! Which is it, magnetic field or e/m strength?This means that if the Earth were denser, you would weigh less, not more. You weigh less on the Moon not because it is less dense, or because it has less mass, but because its foundational E/M field is stronger. And its foundational E/M field is stronger because the Moon’s radius is smaller than the Earth’s. Although the Moon’s body is less dense, as a whole, its E/M field is more dense, on the surface. And this is simply because it has so much less surface area than the Earth (13 times less). You can’t just look at mass or density, you have to look at field lines; and the density of those field lines at the surface determines the strength of the foundational E/M field.
.
How does photon e/m create gravity?
Regards,
Daniel
- Shoot Forth Thunder -
- 303vegas
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Re: Miles Mathis 'What is G?'
Hows this for as simple theory on 'G': Static Cling. This must make me the bestest physicist. You may go about your business now...
love from lancashire!
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Re: Miles Mathis 'What is G?'
thanks , guys.....but I am still lost....but because its foundational E/M field is stronger. And its foundational E/M field is stronger because the Moon’s radius is smaller than the Earth’s. Although the Moon’s body is less dense, as a whole, its E/M field is more dense, on the surface.
re: foundational E/M field? The E/M emitted from the moon/Earth?
Why would the moon's E/M be more dense?
"It is dangerous to be right in matters where established men are wrong."
"Doubt is not an agreeable condition, but certainty is an absurd one."
"Those who can make you believe absurdities, can make you commit atrocities." Voltaire
"Doubt is not an agreeable condition, but certainty is an absurd one."
"Those who can make you believe absurdities, can make you commit atrocities." Voltaire
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