Greetings Oz

Just a guess here but remember they want as much energy as possible transferred to accelerating the protons. After all this is a particle accelerator / 'Atom smasher'.

Normally magnetic field strength is calculated by the number of coils times the amount of current running through those coils in amps. In the case of a simple coil this is an easy calculation. In the case of the LHC we know that the total peak power input is around 12,000 amps but that is for all the superconducting magnets of which there are 1232 dipoles, 392 quadrupoles and 10,000 superconducting magnets in total. Not sure how that all works out to coil equivalents but remember these 'coils' are actually positioned at right angles to the main ring in order to accelerate the protons. They are relatively far apart and there would also be some degree of magnetic field cancellation through current eddies. This is the main magnetic force of the LHC and this is what you should be looking at. Frankly I wouldn't know where to begin but my gut instincts tell me it's not going to amount to much over 27 kilometers.

As for the magnetic field of the accelerated charge itself:

Each amp of course being equal to 6.242×10^18 protons per second. Since the particles make it to 11 km/sec less than the speed of light for the last part in the main ring it would be roughly 300,000/27 or 11,111 times per second. That would be the number of 'coils' traveled per second.

Remember that the extremely high 6.5 TeV (voltage) of each proton accelerated has nothing to do with the magnetic field strength itself other than being a direct product of it.

The amount of proton charge is 2,808 bundles X 115x10^9 as per Wiki. If I am right then the number of amps is only 3.22 x 10^14 / 6.242 x 10^18 so roughly 1/2 of 10^-4 amps or .0005 amps which is not much. When multiplied by the 11,111 potential coils a magnetic field strength of about 5 ampere-turns would result if all the protons were traveling in the same direction.

However half of this charge accelerates clockwise and half accelerates counter-clockwise which should cancel the field strength out to zero unless I am missing something like alternative magnetic configurations.

Great thought exercise Oz... Looking forward to getting completely eviscerated on this answer lol!

https://en.wikipedia.org/wiki/Large_Hadron_Colliderhttps://en.wikipedia.org/wiki/Amperehttps://en.wikipedia.org/wiki/Ampere-turnBTW I see that the 'cosmic wheel' (of Shiva in this case) is once again prominently displayed at CERN.

http://www.strangerdimensions.com/2014/ ... star-gate/